If the effective current is 3.5 A, what is the peak-to-peak value of the applied AC current?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $9.99Unlock all

Study for the NEIEP Electrical Fundamentals Test. Use flashcards and multiple choice questions, each with hints and explanations. Get ready for your exam!

Multiple Choice

If the effective current is 3.5 A, what is the peak-to-peak value of the applied AC current?

Explanation:
RMS (effective) current is 3.5 A, and for a sinusoidal AC, the peak value is Ipeak = Irms × sqrt(2) ≈ 3.5 × 1.414 ≈ 4.95 A. The peak-to-peak current is twice the peak value, so Ipp ≈ 2 × 4.95 ≈ 9.9 A. Therefore the peak-to-peak value is about 9.9 A.

RMS (effective) current is 3.5 A, and for a sinusoidal AC, the peak value is Ipeak = Irms × sqrt(2) ≈ 3.5 × 1.414 ≈ 4.95 A. The peak-to-peak current is twice the peak value, so Ipp ≈ 2 × 4.95 ≈ 9.9 A. Therefore the peak-to-peak value is about 9.9 A.

More Multiple Choice Questions
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy