What is the peak value of 65 volts RMS?

Study for the NEIEP Electrical Fundamentals Test. Use flashcards and multiple choice questions, each with hints and explanations. Get ready for your exam!

Multiple Choice

What is the peak value of 65 volts RMS?

Explanation:
For a sine wave, the RMS value is the peak value divided by sqrt(2). So the peak value equals the RMS value times sqrt(2). With 65 V RMS, the peak is 65 × sqrt(2) ≈ 65 × 1.41421356 ≈ 91.92 V, which rounds to 91.94 V. That’s why 91.94 V is the correct peak value. The other numbers come from mixing up the conversion: 65 V is the RMS itself, not the peak; 46.0 V would be 65 divided by sqrt(2), which would be the RMS if the peak were 65 V; and 130 V would be 2 × 65, which uses a factor of 2 instead of sqrt(2).

For a sine wave, the RMS value is the peak value divided by sqrt(2). So the peak value equals the RMS value times sqrt(2). With 65 V RMS, the peak is 65 × sqrt(2) ≈ 65 × 1.41421356 ≈ 91.92 V, which rounds to 91.94 V. That’s why 91.94 V is the correct peak value.

The other numbers come from mixing up the conversion: 65 V is the RMS itself, not the peak; 46.0 V would be 65 divided by sqrt(2), which would be the RMS if the peak were 65 V; and 130 V would be 2 × 65, which uses a factor of 2 instead of sqrt(2).

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